The Random Bar

[Something Invisible]

-seductive hello

wait. not that one. sorry.
this simple one. I can't figure out. :p

3/x = 9/2(x+2)

Follow PEMDAS (Parenthesis, Exponents, Multiply, Divide, Add, Subtract)
3/x = 9/2(x+2)
Distribute the 2 to the X and the 2
then it's 2x + 4

3/x = 9/2x+4

Think you can work this out?  

[Something Invisible]

Something Invisible

-seductive hello

wait. not that one. sorry.
this simple one. I can't figure out. :p

3/x = 9/2(x+2)

Follow PEMDAS (Parenthesis, Exponents, Multiply, Divide, Add, Subtract)
3/x = 9/2(x+2)
Distribute the 2 to the X and the 2
then it's 2x + 4

3/x = 9/2x+4

Think you can work this out?

Oh wait, you said you're working with fractions?  

[Abstinence II]

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..  

[Silver Sage-General]

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo  

[Lady Eevee]

Information required to complete the questions

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.


1. Give the value, to three significant figures, of x.

[15 marks]


2. An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

[100+90-7685*58/92 marks]


3. Prove that the triangle above exists.

[25 marks]


4. What is the area of a octagon of side length y, in cubic inches. (Note that this question uses non-euclidean goemetry)

[2πr marks]


5. Through cunning use of Pythaogoras' Theorem, prove that aliens do not exist.

[-0 marks]


6. If math, then what does y smell like?

[-10 marks]


7. What is the answer of this question?  

[Abstinence II]

Silver Sage-General

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4  

[Something Invisible]

-seductive hello

Silver Sage-General

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Are those fractions?  

[Silver Sage-General]

-seductive hello

Silver Sage-General

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Multiply each number by (s-2/1). (s-2) will be your variable for now so you can keep it as is. Bring together both numbers that have this variable and solve. :3  

[Abstinence II]

Something Invisible

-seductive hello

Silver Sage-General

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Are those fractions?

Yep.

@Silver: So what's the common denominator?  

[Silver Sage-General]

-seductive hello

Something Invisible

-seductive hello

Silver Sage-General

-seductive hello

Silver Sage-General

Sorry was reading. OOooo I luv math.

Hmm..well you can simplify it by getting rid of the parentheses and taking the 4 out of the bottom of the right fraction. so you get:

3/x = 9/2x + 4.

After that you multiply both sides by x/1.

x/1(3/x) = (9/2x + 4 )x/1

3 = 9/2 + 4x.

Subtract the fraction from both sides and solve.

And that's all. ^^

Haha Well, I figured it out and it's actually 4. o-o..

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Are those fractions?

Yep.

@Silver: So what's the common denominator?

um its asking for one?  

[Lady Eevee]

ANSWER MY MATH QUESTIONS!

Lady Eevee

Information required to complete the questions

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.


1. Give the value, to three significant figures, of x.

[15 marks]


2. An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

[100+90-7685*58/92 marks]


3. Prove that the triangle above exists.

[25 marks]


4. What is the area of a octagon of side length y, in cubic inches. (Note that this question uses non-euclidean goemetry)

[2πr marks]


5. Through cunning use of Pythaogoras' Theorem, prove that aliens do not exist.

[-0 marks]


6. If math, then what does y smell like?

[-10 marks]


7. What is the answer of this question?

 

[Abstinence II]

Silver Sage-General

-seductive hello

Something Invisible

-seductive hello

Silver Sage-General

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Are those fractions?

Yep.

@Silver: So what's the common denominator?

um its asking for one?

Well, for this equation, yeah.  

[Silver Sage-General]

-seductive hello

Silver Sage-General

-seductive hello

Something Invisible

-seductive hello

Silver Sage-General

mkay owo

o wo Well, there's one more problem that I need to figure and the answer is 130 but I don't know how to get it..

question : 7/8 - 16/s-2 = 3/4

Are those fractions?

Yep.

@Silver: So what's the common denominator?

um its asking for one?

Well, for this equation, yeah.

Lol I dunno then. Maybe my method was different from theirs.  

[Abstinence II]

Silver Sage-General

-seductive hello

Silver Sage-General

-seductive hello

Something Invisible

Are those fractions?

Yep.

@Silver: So what's the common denominator?

um its asking for one?

Well, for this equation, yeah.

Lol I dunno then. Maybe my method was different from theirs.

lmao well, okay then. Thanks for the help!  

[Silver Sage-General]

You're welcome. ^^

Time to lock up so I'll see you all later. ;D